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  • Need solution for RD Sharma Maths Class 12 Chapter 17 Maxima and Minima Excercise Case Study Based Questions question 6 subquestion (iv)

Need solution for RD Sharma Maths Class 12 Chapter 17 Maxima and Minima Excercise Case Study Based Questions question 6 subquestion (iv)

Answers (1)

Answer:   \frac{14 \pi}{\pi+4}

Hint: use basics.

Solution:

2 x+\pi y=14

As we know,

\begin{aligned} &x=\frac{28 \pi}{4+\pi} \\ & \end{aligned}

=2\left(\frac{28 \pi}{4+\pi}\right)+\pi y=14

\begin{aligned} &\left(\frac{56 \pi}{4+\pi}\right)+\pi y=14 \\ & \end{aligned}

\frac{56 \pi}{4+\pi}=14-\pi y

\begin{aligned} -14+\frac{56 \pi}{4+\pi} &=-\pi y \\ \end{aligned}

-56 \pi-14 \pi+56 \pi =-\pi y(4+\pi) . \\

-\frac{14 \pi}{\pi+4} =-y

\frac{14 \pi}{\pi+4}=\mathrm{y}

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