Get Answers to all your Questions

header-bg qa

Need solution for RD Sharma Maths Class 12 Chapter 17 Maxima and Minima Excercise Case Study Based Questions question 6 subquestion (v)

Answers (1)

Answer:   \frac{196 \pi-2}{\pi(\pi+4)}

Hint: use basic concepts and concepts of maxima and minima.


\begin{aligned} &A=\pi\left(\frac{14-2 x}{4}\right)^{2}+\frac{x^{2}}{4^{2}} \\ & \end{aligned}

=\pi\left(\frac{14-2 x}{4}\right)^{2}+\frac{x^{2}}{16} \\

=\frac{\pi\left(196+4 x^{2}-56 x\right)}{16}+\frac{x^{2}}{16}

Put x = -1

\begin{aligned} A &=\frac{\pi(196)-2}{\pi(\pi+4)} \\ & \end{aligned}

=\frac{196 \pi-2}{\pi(\pi+4)}


Posted by


View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support