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Please solve RD Sharma class 12 Chapter Maxima and Minima exercise Multiple choice question, question 35 maths textbook solution.

Answers (1)

Answer: (b) 12

Hint: For local maxima or minima, we must have f'(x)=0.

Given: Maximum slope of the curve y=-x^3+3x^2+9x-27

Solution:

Slope of the curve is given by

m=\frac{dy}{dx}=-3x^2+6x+9

\frac{dm}{dx}=-6x+6  

\frac{d^2m}{d^2x}=-6<0            ∀x

So, m is maximum, when x = 1

Putting x = 1 in the slope of the curve, we get, m = -3+6+9=12

The slope is maximum at the point (1, 12).

Maximum value of slope is m = 12

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