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  • Provide solution for RD Sharma maths class12 Chapter Maxima and Minima exercise Multiple choice question, question 7.

Provide solution for RD Sharma maths class12 Chapter Maxima and Minima exercise Multiple choice question, question 7

Answers (1)

Answer: option(a) \frac{1}{2}  

Hint: For local maxima or minima, we must have f'(x) =0.

Given: f(x)=x-x^2

Solution:

We have,

f(x)=x-x^2

f'(x)=1-2x

For maxima and minima f'(x)=0

\Rightarrow 1-2x=0

\Rightarrow x=\frac{1}{2}

Now,

f''(x)=-2<0

So, x=\frac{1}{2} is a point of local maxima.

The local maximum value is given by f\left (\frac{1}{2} \right )=\frac{1}{2}-\frac{1}{4}=\frac{1}{2}

 

Posted by

infoexpert24

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