Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide Solution for RD Sharma Class 12 Chapter 17 Maxima and Minima Exercise Case Study Based Questions question 8 subquestion (iii)

Provide Solution for RD Sharma Class 12 Chapter 17 Maxima and Minima Exercise Case Study Based Questions question 8 subquestion (iii)

Answers (1)

Answer:  \frac{8\left(200-x^{2}\right)}{\sqrt{400-x^{2}}}

Hint: use the concept of maxima and minima.

Solution:

\begin{aligned} \mathrm{x}^{2}+\mathrm{y}^{2} &=400 \\ \ \end{aligned}

{y}^{2} =400-\mathrm{x}^{2} \\

\mathrm{~A}=1 \times \mathrm{b} \\

\mathrm{A}=2 \mathrm{x} \times 2 \sqrt{400-\mathrm{x}^{2}} \\

= 4 \mathrm{x} \sqrt{400-\mathrm{x}^{2}}

\begin{aligned} &\frac{d A}{d x}=4 \sqrt{400-4 x^{2}}+4\left(\frac{\left(-2 x^{2}\right)}{2 \sqrt{400-x^{2}}}\right) \\ \end{aligned}

\frac{d A}{d x}=\frac{8\left(200-x^{2}\right)}{\sqrt{40 x-x^{2}}}

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board exams twice a year from 2025, no plan for semesters: MoE
anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question