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Provide solution for RD Sharma maths class12 Chapter Maxima and Minima exercise 17.5 question 36.

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10 items

Hint: For maximum or minimum value of P, we must have \frac{dP}{dx}=0

Given: Profit = S.P - C.P

P= x\left ( 50-\frac{x}{2} \right )-\left ( \frac{x^2}{4}+35x+25 \right )

Solution: P= x\left ( 50-\frac{x}{2} \right )-\left ( \frac{x^2}{4}+35x+25 \right )

\begin{aligned} &P=50 x-\frac{x^{2}}{2}-\frac{x^{2}}{4}-35 x-25 \\ &\frac{d P}{d x}=50-x-\frac{x}{2}-35 \\ &\frac{d P}{d x}=0 \\ &15-\frac{3 x}{2}=0 \\ &15=\frac{3 x}{2}, x=\frac{30}{3}=10 \end{aligned}



Profit is the maximum if daily output is 10 units.


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