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Please Solve RD Sharma Class 12 Chapter 17 Maxima and Minima Exercise Case Study Based Questions question 1subquestion (ii) Maths Textbook Solution.

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Answer:  \frac{2}{\pi}\left ( 100x-x^2 \right )

Hint: Area of rectangle = length × breadth


 Area  =Area of rectangle 

=x\times y

\\ since, 2x+ \pi y =200\

\ \pi y =200-2x\

y =\frac{1}{\pi}(200-2x)

Area =  x\times \frac{1}{\pi}(200-2x)

Area =  \frac{1}{\pi} \left ( 200x-2x^{2} \right )

         =\frac{2}{\pi} \left ( 100x-x^{2}\right )


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