Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 Chapter maxima and minima exercise 17.5 question 6 sub question (i) maths textbook solution.

Please solve RD Sharma class 12 Chapter maxima and minima exercise 17.5 question 6 sub question (i) maths textbook solution.

Answers (1)

\frac{L}{2}

Hint: For maximum or minimum value of we must have \frac{dm}{dx}=0

Given: m=\frac{WL}{2}x-\frac{W}{2}x^2

Solution: m=\frac{WL}{2}x-\frac{W}{2}x^2

\begin{aligned} &\frac{d m}{d x}=\frac{W L}{2}-2 \frac{W}{2} x \\ &=\frac{W L}{2}-W x \end{aligned}

For maximum or minimum ,

\frac{dm}{dx}=0

\frac{WL}{2}-Wx=0

\frac{WL}{2}=Wx

x=\frac{L}{2}

\frac{d^2m}{dx^2}=-W<0

So m is maximum at x=\frac{L}{2}

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Exam 2026 LIVE: Computer science, IT, IP papers ends; question paper analysis, updates
anam-khan

CBSE Board 12th Exams 2026 LIVE: Class 12 political science exam 'moderate' in difficulty; simple MCQs
anam-khan

CBSE Class 12 Economics Analysis: Students find exam moderately difficult; questions mostly application-based

Latest Question