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Provide Solution for RD Sharma Class 12 Chapter 17 Maxima and Minima Exercise Case Study Based Questions question 8 subquestion (ii)

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Answer:  \mathrm{A}=4 \mathrm{x} \sqrt{400-\mathrm{x}^{2}}

Hint: use the formula of area of rectangle.


Area =l\times b

\mathrm{A}=2 \mathrm{x} \times 2 \mathrm{y}
As we know,

\begin{aligned} &\mathrm{x}^{2}+\mathrm{y}^{2}=400 \\ \end{aligned}

\mathrm{y}^{2}=400-\mathrm{x}^{2} \\

\mathrm{y}=\sqrt{400-\mathrm{x}^{2}} \\

\mathrm{~A}=2 \mathrm{x} \times 2 \sqrt{400-\mathrm{x}^{2}} \\

\mathrm{~A}=4 \mathrm{x} \sqrt{400-\mathrm{x}^{2}}

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