Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD sharma class 12 chapter 28 The Plane exercise 28.8, question 19

Explain solution RD sharma class 12 chapter 28 The Plane exercise 28.8, question 19

Answers (1)

The answer of the given question is x+2y+3z=4.

Hints:-  We know that, equation of a plane passing through the line of intersection of two planes

a_{1}x+b_{1}y+c_{1}z+d_{1}=0 and a_{2}x+b_{2}y+c_{2}z+d_{2}=0 is given by

\left (a_{1}x+b_{1}y+c_{1}z+d_{1} \right )+k\left ( a_{2}x+b_{2}y+c_{2}z+d_{2} \right )=0


Given:- x+y+z=1\\ 2x+3y+4z=5

∴ Required equation of plane is x+y-1+z+\lambda (2x+3y+4z-5)=0  for some \lambda

i.e. (1+2\lambda) x+(1+3\lambda) y+(1+4\lambda) z=(1+5\lambda)
According to question 2\left ( \frac{1+5\lambda}{1+3\lambda} \right )=3\left ( \frac{1+5\lambda}{1+4\lambda} \right )

Solving we get \lambda =-1

Thus the equation of required plane is
-x-2y-3z=-4\\ x+2y+3z=4

Posted by

Info Expert 29

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam 2025: Class 9, 11 registration begins today; fee details, guidelines
anam-khan

Submit list of candidates for CBSE board exams 2025 correctly, on time: Schools reminded
anam-khan

CBSE sample paper 2024-25, marking scheme out for skill education subjects

Latest Question