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Provide solution for RD Sharma maths Class 12 Chapter 28 The Plane Exercise 28.9 Question 3 textbook solution.

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Answer : The answer of the given question is 3 units

Hint : P=\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|

Given :

       Point A(2,3,-5)

       Plane x+2 y-2 z-9=0

Solution :

We know, the distance of point  \left(x_{1}, y_{1}, z_{1}\right) from the plane

a x+b y+c z+d=0 Is given by

P=\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|

Putting the necessary values

Distance of the plane from A=\left|\frac{1 \times 2+2 \times 3+(-2) \times(-5)-9}{\sqrt{1^{2}+2^{2}+(-2)^{2}}}\right|=3 \text { Units }

Hence the distance of the plane (2,3,-5) from the plane x+2 y-2 z-9=0 is 3 units

 

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