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  • Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 28 The Plane  Exercise 28.13 Question 16 Sub Question 2 Maths Textbook Solution.

Answers (1)

2\left(4-\lambda^{2}\right)-0\left(2-\lambda^{2}\right)-2\left(\lambda^{2}-2\right)=0

8-2 \lambda^{2}-2 \lambda^{2}+4=0

\lambda^{2}+\lambda^{2}-6=0

Let \lambda^{2}=t then

(t+3)(t-2)=0

Put value of t

\left(\lambda^{2}+3\right)\left(\lambda^{2}-2\right)=0is neglected because direction cosine cannot be imaginary

\lambda^{2}=-3

Therefore, \lambda=\pm \sqrt{2}

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