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please solve RD sharma class 12 chapter 28 The Plane exercise 28.8 question 1 maths textbook solution

Answers (1)

The answer of the given question is 2x-3y+z=7.

Hint:-  By find and putting the value of k

Given:- 2x-3y+z=7 and point (1,-1,2)

Solution:-  Given equation of plane is 2x-3y+z=7                         … (i)

We know that equation of a plane parallel to given plane (i) is

2x-3y+z+k=0                                   …(ii)

As given that, plane (ii) is passing through the point (1,-1,2) so it satisfy the plane (ii)

2(1)-3(-1)+2+k=0\\ k=-7

Put the value of k in equation (ii),

2x-3y+z-7=0

So, equation of the required plane is,  2x-3y+z=7                     

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