# Need solution for RD Sharma maths Class 12 Chapter 28 The Plane Exercise 28.9 Question 7 textbook solution.

Hint :

$P=\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|$

Given :

Points : $A(2,3,5)$

Plane : $z = 0$

Solution :

We know, the distance of point  $\left(x_{1}, y_{1}, z_{1}\right)$ from the plane

$p: a x+b y+c z+d=0$  Is given by

$P=\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|$

Putting the values

$P=\left|\frac{0 \times 2+0 \times 3+1 \times 5+0}{\sqrt{0^{2}+0^{2}+1^{2}}}\right|=5 \text { Unit }$

The distance of the point $(2,3,5)$ from the xy-plane is 5 unit

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