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Need solution for RD Sharma maths Class 12 Chapter 28 The Plane Exercise 28.9 Question 8 textbook solution.

Answers (2)

Answer : The answer of the given question is \frac{9}{\sqrt{78}} unit

Hint :

      P=\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|

Given :

   Points : A(3,3,3)

   Plane : \vec{r} \cdot(5 \hat{i}+2 \hat{j}-7 \hat{k})+9=0, which in Cartesian form

Solution :

5 x+2 y-7 z+9=0 and point (3,3,3)

We know the distance of point \left(x_{1}, y_{1}, z_{1}\right) from the plane

p: a x+b y+c z+d=0 Is given by

P=\left|\frac{a x_{1}+b y_{1}+c z_{1}+d}{\sqrt{a^{2}+b^{2}+c^{2}}}\right|

Putting the values

P=\left|\frac{5 \times 3+2 \times 3+(-7) \times 3+9}{\sqrt{5^{2}+2^{2}+(-7)^{2}}}\right|=\frac{9}{\sqrt{78}} \text { Units }

The distance of the point (3,3,3) from the plane,

\vec{r} \cdot(5 \hat{i}+2 \hat{j}-7 \hat{k})+9=0 \text { is } \frac{9}{\sqrt{78}} \text { Units }

Posted by

infoexpert23

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Shiva Ram

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