Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter 28 The Plane exercise Fill in the blank question 19

Need solution for RD Sharma maths class 12 chapter 28 The Plane exercise Fill in the blank question 19

Answers (1)

Answer:

 3 units is the required distance.

Hint:

 use vector dot product to find the distance

Given:

 2x+y-2z-6=0 \text { and } 4x+2y-4z=0

Solution:

Let

\begin{aligned} &P_{1}\rightarrow 2x+y-2z-6=0\\ &ax+by+cz+d_{1}=0\\ &P_{2}\rightarrow 4x+2y-4z=0\\ &ax+by+cz+d_{2}=0\\ \end{aligned}

\begin{aligned} &\because P_{1}\left | \right |P_{2} \end{aligned}

\begin{aligned} &\text { Distance between } P_{1} \text { and } P_{2}=\left | \frac{d_{2}-d_{1}}{\sqrt{a^{2}+b^{2}+c^{2}}} \right |\\ &=\left | \frac{0-6}{\sqrt{2^{2}+1^{2}+(-2)^{2}}} \right |=\left | \frac{-6}{4+1+4} \right |\\ &=3\: units \end{aligned}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2027 LIVE: Class 10, 12 board exam schedule soon; passing marks, paper pattern
anam-khan

CBSE Class 12 West Asia special exam date sheet 2026 out; admit cards from October 12
anam-khan

CBSE Class 10, 12 private exams 2026-27 registration begins on cbse.gov.in, check eligibility and fees

Latest Question