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Provide Solution For  R. D. Sharma Maths Class 12 Chapter determinants Exercise 5.2 Question 2 Sub Question 7 Maths Textbook Solution.

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Answer:\left|\begin{array}{lll} 49 & 1 & 6 \\ 39 & 7 & 4 \\ 26 & 2 & 3 \end{array}\right|=0

Hint: We will try to do any two column or row equal

Given:\left|\begin{array}{ccc} 49 & 1 & 6 \\ 39 & 7 & 4 \\ 26 & 2 & 3 \end{array}\right|

Solution: \left|\begin{array}{ccc} 49 & 1 & 6 \\ 39 & 7 & 4 \\ 26 & 2 & 3 \end{array}\right|

\begin{aligned} &\text { Applying } C_{3} \rightarrow 8 \times C_{3}+C_{2} \\ &=\left|\begin{array}{lll} 49 & 1 & 6 \times 8+1 \\ 39 & 7 & 4 \times 8+7 \\ 26 & 2 & 3 \times 8+2 \end{array}\right| \\ &=\left|\begin{array}{lll} 49 & 1 & 48+1 \\ 39 & 7 & 32+7 \\ 26 & 2 & 24+2 \end{array}\right| \\ &=\left|\begin{array}{lll} 49 & 1 & 49 \\ 39 & 7 & 39 \\ 26 & 2 & 26 \end{array}\right| \end{aligned}

If any two rows or columns of a determinant are identical.

The value of the determinant is zero

=0 \quad\left(\because C_{1}=C_{3}\right)

Hence\left|\begin{array}{lll} 49 & 1 & 6 \\ 39 & 7 & 4 \\ 26 & 2 & 3 \end{array}\right|=0

 

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