Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need RD Sharma solution for Maths Class 12 Chapter 5 Determinants Exercise Very short question Question 9 for maths textbook solution.

Need RD Sharma solution for Maths Class 12 Chapter 5 Determinants Exercise Very short question Question 9 for maths textbook solution.

Answers (1)

Answer:0

Hint: Here we use basic concept of matrix multiplication and determinant of  matrix

Given: A=\left[\begin{array}{cc} 1 & 2 \\ 3 & -1 \end{array}\right] B=\left[\begin{array}{cc} 1 & 0 \\ -2 & 0 \end{array}\right] \text { Find }|A B|

Solution :

For \left | AB \right | let's Find AB
Here, A and B are 2 \times 2 order of matrix.
So matrix multiplication is possible.

\begin{aligned} &A \times B=\left[\begin{array}{cc} 1 & 2 \\ 3 & -1 \end{array}\right] \times\left[\begin{array}{cc} 1 & 0 \\ -2 & 0 \end{array}\right] \\ &\; \; \; \; \; \; \; \; \; \; =\left[\begin{array}{cc} 1 \times 1+2(-2) & 0+0 \\ 3+2 & 0+0 \end{array}\right] \\ &\; \; \; \; \; A B=\left[\begin{array}{cc} -3 & 0 \\ 5 & 0 \end{array}\right] \end{aligned}

\begin{aligned} &\rightarrow \text { Let's Find }|A B|\\ &|A B|=[-3 \times 0]-[5 \times 0]\\ &\; \; \; \; \; \; \; =0-0\\ &|A B|=0 \end{aligned}

Posted by

infoexpert23

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10, 12 compartment 2024 exams today for 2.5 lakh students; exam timings, guidelines
anam-khan

CBSE compartment admit card 2024 out at cbse.gov.in; exams from July 15
anam-khan

Reports saying CBSE cannot conduct board exams twice a year currently ‘totally incorrect’; board denies claims

Latest Question