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  • Need solution for RD Sharma maths class 12 chapter Determinants exercise 5.1 question 10 subquestion (v)

Need solution for RD Sharma maths class 12 chapter Determinants exercise 5.1 question 10 subquestion (v)

Answers (1)

Answer:

x=2

Hint:

Take determinant of matrix on both side and equate it.

Given:

\begin{aligned} &\left|\begin{array}{ll} x+1 & x-1 \\ x-3 & x+2 \end{array}\right|=\left|\begin{array}{cc} 4 & -1 \\ 1 & 3 \end{array}\right| \end{aligned}

Solution:

\begin{aligned} &\left|\begin{array}{ll} x+1 & x-1 \\ x-3 & x+2 \end{array}\right|=\left|\begin{array}{cc} 4 & -1 \\ 1 & 3 \end{array}\right| \\ &(x+1)(x+2)-(x-3)(x-1)=12+1 \\ &x^{2}+3 x+2-x^{2}+4 x-3=13 \\ &7 x-1=13 \\ &7 x=14 \\ &x=2 \end{aligned}

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