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Need solution for RD Sharma maths class 12 chapter Determinants exercise 5.1 question 10 subquestion (i)

Answers (1)

Answer:

x=\pm \sqrt{3}

Hint:

Take determinant of matrix on both side and equate it.

Given:

\begin{aligned} &\left|\begin{array}{ll} 2 & 4 \\ 5 & 1 \end{array}\right|=\left|\begin{array}{ll} 2 x & 4 \\ 6 x & x \end{array}\right| \end{aligned}

Solution:

\begin{aligned} &\left|\begin{array}{ll} 2 & 4 \\ 5 & 1 \end{array}\right|=\left|\begin{array}{ll} 2 x & 4 \\ 6 x & x \end{array}\right| \\ &2-20=2 \mathrm{x}^{2}-24 \\ &-18=2 \mathrm{x}^{2}-24 \\ &2 \mathrm{x}^{2}=6 \\ &\mathrm{x}^{2}=3 \\ &\mathrm{x}=\pm \sqrt{3} \end{aligned}

Posted by

Gurleen Kaur

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