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Please solve RD Sharma maths Class 12 Chapter 5 Determinants Exercise VSQ Question 42 maths textbook solution.

Answers (1)

Answer:32

Hint: Here we use basic concept of determinant of matrix

Given:

\begin{aligned} &|A|=4\\ &A \text { is } 3 \times 3 \text { order of matrix } \text { So, } n=3 \end{aligned}

Solution :

\begin{aligned} &\text { Here }|2 A|\\ &\rightarrow|k A|=k^{n}|A| \end{aligned}

Where n = order of matrix

k = constant

\begin{aligned} &\text { So, }|2 A|=2^{n}|A| \\ &|2 A|=2^{3} \times 4 \\ &|2 A|=8 \times 4=32 \end{aligned}

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