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#Maths
#R.D. Sharma
#CBSE 12 Class
#School
#RD Sharma Vol. 1 Class 12
#Determinants

#1.3
#5.2
#5.3
#5.4
#5.5
#5.1
#9.12
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)

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Need solution for RD Sharma maths Class 12 Chapter 5 Determinants Exercise VSQ Question 54 maths textbook solution.

Answers (1)

Answer: 2

Hint: Here we use basic concept of determinant of matrix

Given: $\left|\begin{array}{cc} x+3 & -2 \\ -3 x & 2 x \end{array}\right|=8$

Solution : $(x+3)(2 x)-[-3 x(-2)]=8$

$\begin{aligned} &2 x^{2}+6 x-6 x=8 \\ &2 x^{2}=8 \\ &x^{2}=4 \\ &x=\pm 2, x \neq-2 \text { as } x \in N \end{aligned}$

Hence, $x = 2$

Posted by

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Need solution for RD Sharma maths Class 12 Chapter 5 Determinants Exercise VSQ Question 54 maths textbook solution.

Answers (1)

Posted by

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