Get Answers to all your Questions

header-bg qa

provide solution for RD Sharma maths class 12 chapter 5 Determinants exercise  Fill in the blanks question 22

Answers (1)

best_answer

Answer: zero

Hint: Here, we use basic concept of determinant of matrix

Given:  \left[\begin{array}{lll} \left(2^{x}+2^{-x}\right)^{2} & \left(2^{x}+2^{-x}\right)^{2} & 1 \\ \left(3^{x}+3^{-x}\right)^{2} & \left(3^{x}+3^{-x}\right)^{2} & 1 \\ \left(4^{x}+4^{-x}\right)^{2} & \left(4^{x}+4^{-x}\right)^{2} & 1 \end{array}\right]

Solution:  Here, clearly 2 column has same value

                According to property of determinant, if two column has same value then determinant of matrix should be zero.

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads