Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide Solution For R D Sharma Maths Class 12 Chapter determinants Exercise 5.2 Question 26 Maths Textbook Solution.

Provide Solution For  R D Sharma Maths Class 12 Chapter  determinants Exercise 5.2 Question 26 Maths Textbook Solution.

Answers (1)

Answer:\left|\begin{array}{ccc} 1 & 1+p & 1+p+q \\ 2 & 3+2 p & 4+3 p+2 q \\ 3 & 6+3 p & 10+6 p+3 q \end{array}\right|=1

Hint we will convert element of C_{1} into zero

Given:\left|\begin{array}{ccc} 1 & 1+p & 1+p+q \\ 2 & 3+2 p & 4+3 p+2 q \\ 3 & 6+3 p & 10+6 p+3 q \end{array}\right|=1

Solution:

\begin{aligned} &\text { L.H.S }\left|\begin{array}{ccc} 1 & 1+p & 1+p+q \\ 2 & 3+2 p & 4+3 p+2 q \\ 3 & 6+3 p & 10+6 p+3 q \end{array}\right|\\ &\text { On applying } \mathrm{R}_{2} \rightarrow R_{2}-2 R_{1} \text { and } \mathrm{R}_{3} \rightarrow R_{3}-3 R_{1}\\ &=\left|\begin{array}{ccc} 1 & 1+p & 1+p+q \\ 0 & 1 & 2+p \\ 0 & 3 & 7+3 p \end{array}\right| \end{aligned}

\begin{aligned} &\text { On expanding w.r.t } \mathrm{C}_{1}\\ &=1\left|\begin{array}{cc} 1 & 2+p \\ 3 & 7+3 p \end{array}\right|-0\left|\begin{array}{cc} 1+p & 1+p+q \\ 3 & 7+3 p \end{array}\right|+0\left|\begin{array}{cc} 1+p & 1+p+q \\ 1 & 2+p \end{array}\right|\\ &=1\{1(7+3 p)-3(2+p)\}-0+0\\ &=7+3 p-6-3 p\\ &=1\\ &=R \cdot H \cdot S \end{aligned}

Hence it is proved that

\left|\begin{array}{ccc} 1 & 1+p & 1+p+q \\ 2 & 3+2 p & 4+3 p+2 q \\ 3 & 6+3 p & 10+6 p+3 q \end{array}\right|=1

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question