#### Please solve RD Sharma class 12 chapter 5 Determinants exercise Fill in the blanks question 5 maths textbook solution

Answer: $R-\left | 1 \right |$

Hint: Here, we use basic concept of non-singular matrix

Given:  $A=\begin{bmatrix} a & 2\\ 2&4 \end{bmatrix}$ is non-singular

Solution: Here, A is non-singular

So, $\left | A \right |\neq 0$

$\begin{bmatrix} a & 2\\ 2&4 \end{bmatrix}\neq 0$

$(a(4))-(2)(2)\neq 0$

$4a-4\neq 0$

$4a\neq 4$

$a\neq 1$

So, $a$ should be in $R-\left | 1 \right |$