#### Provide solution for RD Sharma maths class 12 chapter Determinants exercise multiple choise question 22

Correct option (c)

Hint:

Solve both determinants then equating them, we get required value of x

Given:

Here

$\begin{vmatrix} 2x &5 \\ 8 &x \end{vmatrix}=\begin{vmatrix} 6 &-2 \\ 7 &3 \end{vmatrix}$

We have to find the value of x.

Solution:

Here

$\begin{vmatrix} 2x &5 \\ 8 &x \end{vmatrix}=\begin{vmatrix} 6 &-2 \\ 7 &3 \end{vmatrix}$

$\Rightarrow 2x^{2}-40=18+14$

$\Rightarrow 2x^{2}=32+40$

$\Rightarrow 2x^{2}=72$

$\Rightarrow x^{2}=36$

$\Rightarrow x=\pm 6$