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Need solution for RD Sharma maths Class 12 Chapter 5 Determinants Exercise VSQ Question 33 maths textbook solution.

Answers (1)

Answer: -81

Hint: Here we use basic concept of determinant of matrix

Given : |A|=-1

\begin{aligned} &|B|=3 \\ &|3 A B|=? \end{aligned} A and B 3 \times 3 order of matrices So, n=3

Solution :

Here,

\begin{aligned} &|3 A B|=|3 A| \times|B| \\ &=3^{n}|A| \times|B| \quad\left[|k A|=k^{n}|A|\right] \\ &=3^{3} \times-1 \times 3 \\ &=27 \times 3 \times-1 \\ &|3 A B|=-81 \end{aligned}

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