Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve R.D.Sharma class 12 Chapter 19 Definite Integrals Exercise 19.1 Question 4 Maths textbook Solution.

Please Solve R.D.Sharma class 12 Chapter 19 Definite Integrals Exercise 19.1 Question 4 Maths textbook Solution.

Answers (1)

Answer: \frac{\pi }{4}

Hint: Use indefinite formula to solve the integral and then put the value of limit to get the required answer

Given: \int_{0}^{1}\frac{1}{1+x^{2}}dx

Solution: \int_{0}^{1}\frac{1}{1+x^{2}}dx=\int \tan ^{-1}xdx                            \left [ \int \frac{1}{1+x^{2}}dx=\tan ^{-1}x \right ]

=\tan ^{-1}(1)-\tan ^{-1}(0) \quad\left[\tan \left(\frac{\pi}{4}\right)=1 \Rightarrow \tan ^{-1}(1)=\frac{\pi}{4}, \tan 0=0 \Rightarrow \tan ^{-1}(0)=0\right]

=\left [ \frac{\pi }{4}-0 \right ]=\frac{\pi }{4}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 result verification 2024 application out at cbse.gov.in; last date, fees
anam-khan

CBSE results 2024 later for 102 students over fake certificates; board issues show cause notice
anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know

Latest Question