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Please Solve RD Sharma Class 12 Chapter 19 Definite Integrals Exercise Revision Exercise Question 65 Maths Textbook Solution.

Answers (1)

Answer:   \frac{1}{e^{2}}\left[1-\frac{1}{e}\right]

Hint: To solve the given statement use the formula of  e^{-x}

Given:  \int_{2}^{3} e^{-x} d x

Solution:  \int_{2}^{3} e^{-x} d x

\begin{aligned} &=\left[-e^{-x}\right]_{2}^{3} \\ & \end{aligned}

=\left(-e^{-3}\right)-\left(-e^{-2}\right) \\

=-e^{-3}+e^{-2} \\

=-\frac{1}{e^{3}}+\frac{1}{e^{2}} \\



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