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Explain solution RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 37 maths

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Answer: 1

Hint: you must know the rule of integration

Given: \int_{0}^{2}[x] d x

Solution:  \int_{0}^{2}[x] d x

        \begin{aligned} &=\int_{0}^{1} 0 d x+\int_{1}^{2} 1 d x \\\\ &=0+[x]_{1}^{2} \\\\ &=2-1 \\\\ &=1 \end{aligned}


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