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Explain solution RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 41 maths

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Answer: \frac{3}{2}

Hint: you must know the rule of integration

Given: \int_{0}^{2} x[x] d x

Solution:  \int_{0}^{2} x[x] d x

=\int_{0}^{1} x[0] d x+\int_{1}^{2} x(1) d x

\begin{aligned} &=\left[0+\frac{x^{2}}{2}\right]_{1}^{2} \\\\ &=\frac{4}{2}-\frac{1}{2}=\frac{3}{2} \end{aligned}


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