Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.3 Question 15 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.3 Question 15 Maths Textbook Solution.

Answers (1)

best_answer

Answer:  4

Hint: We will use the concept of even function to solve the integral.

Given:

                \int_{\frac{-\pi}{2}}^{\frac{\pi}{2}}\{\sin |x|+\cos |x|\} d x

Solution:

\begin{aligned} &I=\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}}\{\sin |x|+\cos |x|\} d x \\ & \end{aligned}

f(-x)=\sin |-x|+\cos |-x|=\sin |x|+\cos |x|=f(x)

                 

\begin{aligned} &f(x) \text { is a even function }\\ & \end{aligned}

I=2 \int_{0}^{\frac{\pi}{2}}(\sin x+\cos x) d x

\begin{aligned} &{\left[\text { for even function } \int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} x d x=2 \int_{0}^{\frac{\pi}{2}} x d x\right]} \\ & \end{aligned}

I=2[-\cos x+\sin x]_{0}^{\frac{\pi}{2}} \\

I=2[(0+1)-(-1-0)] \\

I=2(2)=4

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE, JKBOSE, Assam board exams today; timings, passing marks, key guidelines
anam-khan

CBSE bans use of ChatGPT, mobile during board exam 2025; warns students of action for spreading rumors
anam-khan

Delhi metro to prioritise CBSE Class 10, 12 students for frisking, ticketing during board exam 2025

Latest Question