Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve R.D.Sharma class 12 Chapter 19 Definite Integrals Exercise 19.1 Question 7 Maths textbook Solution.

Please Solve R.D.Sharma class 12 Chapter 19 Definite Integrals Exercise 19.1 Question 7 Maths textbook Solution.

Answers (1)

Answer:\frac{\pi }{2}

Hint:Use indefinite formula to solve the integral and then put the value of limit to get the required answer

Given: \int_{-1}^{1}\frac{1}{1+x^{2}}dx

Solution:\int_{-1}^{1}\frac{1}{1+x^{2}}dx                            \left [ \int \frac{1}{1+x^{2}}dx=\tan ^{-1}x \right ]

=\tan ^{-1}(1)-\tan ^{-1}(-1)                                                \left[\begin{array}{l} \tan \left(\frac{\pi}{4}\right)=1 \Rightarrow \tan ^{-1}(1)=\frac{\pi}{4} \\ \tan ^{-1}(-1)=-\frac{\pi}{4} \end{array}\right]

=\left [ \frac{\pi }{4}+\frac{\pi }{4} \right ]=\frac{2\pi }{4}=\frac{\pi }{2}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2027 Live: 10th, 12th subject-wise exam dates soon; paper pattern, sample paper
anam-khan

CBSE Exam Date 2027 Highlights: Class 10, 12 exam dates soon on cbse.gov.in; private candidate form
anam-khan

CBSE 10th, 12th board exam schedule 2027: Sample papers, passing marks

Latest Question