Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution for RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.4 (b) Question 41 maths textbook solution.

Explain solution for  RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.4 (b) Question 41 maths textbook solution.

Answers (1)

Answer:-  \frac{1}{\pi}

Hints:-  You must know the integral rules of trignometric functions.

Given:-  \int_{0}^{1}|x \sin \pi x| d x

Solution : \int_{0}^{1}|x \sin \pi x| d x

                 \begin{aligned} &=\left[-x \frac{\cos x \pi}{\pi}+\frac{\sin \pi x}{\pi^{2}}\right]_{0}^{1} \\ &=\left[-1 \frac{\cos \pi}{\pi}+\frac{\sin \pi}{\pi^{2}}-0+0\right] \end{aligned}

               \begin{aligned} &=\left[(-1) \frac{-1}{\pi}+0\right] \\ &=\frac{1}{\pi} \end{aligned}

Posted by

infoexpert23

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Congress attacks Dharmendra Pradhan over CBSE row, alleges failures in exam and revaluation process
anam-khan

CBSE retains Coempt for Class 12 revaluation amid OSM controversy, shifts data to its own servers: Reports
anam-khan

CBSE blank marksheet row reaches Supreme Court; Saudi Arabia-based Class 12 student files plea

Latest Question