Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths class 12 chapter 19 Definite Integrals exercise Very short answer type question 27

Provide solution for RD Sharma maths class 12 chapter 19 Definite Integrals exercise Very short answer type question 27

Answers (1)

Answer: \frac{1}{2}

Hint: you must know the rule of integration

Given: \int_{0}^{\frac{\pi}{4}} \sin 2 x \; d x

Solution:  \int_{0}^{\frac{\pi}{4}} \sin 2 x \; d x

\begin{aligned} &=\frac{1}{2}(-\cos 2 x)_{0}^{\frac{\pi}{4}} \\\\ &=-\frac{1}{2}(\cos 2 x)_{0}^{\frac{\pi}{4}} \end{aligned}

\begin{aligned} &=\frac{-1}{2}\left[\cos 2\left(\frac{\pi}{4}\right)-\cos 2(0)\right] \\\\ &=\frac{-1}{2}\left[\cos \frac{\pi}{2}-\cos 0\right] \end{aligned}

\begin{aligned} &=\frac{-1}{2}[0-1] \\\\ &=\frac{1}{2} \end{aligned}

 

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE organises webinar on LOC registration, correction queries for Class 10, 12 board exam 2027
anam-khan

CBSE Board Exam Date 2027 Highlights: Class 10, 12 exam schedule soon at cbse.gov.in
anam-khan

CBSE Board Exams 2027: LOC submission for Classes 10, 12 begins tomorrow; check dates and fees

Latest Question