Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths Class 12 Chapter 19 Definite Integrals Exercise 19.4 (a) Question 14 textbook solution.

Need solution for  RD Sharma maths Class 12 Chapter 19 Definite Integrals Exercise 19.4 (a) Question 14 textbook solution.

Answers (1)

Answer : \frac{7}{2}

Given : \int_{0}^{7} \frac{\sqrt[3]{x}}{\sqrt[3]{x}+\sqrt[3]{7-x}} d x

Hint : Use the formula of \int_{0}^{a} f(x) d x

Solution : I=\int_{0}^{7} \frac{\sqrt[3]{x}}{\sqrt[3]{x}+\sqrt[3]{7-x}} d x-------(1)

I=\int_{0}^{7} \frac{\sqrt[3]{7-x}}{\sqrt[3]{7-x}+\sqrt[3]{x}} d x\left(\int_{0}^{a} f(x) d x=\int_{0}^{a} f(a-x) d x\right)----(2)

Add (1) and (2)

\begin{aligned} &2 I=\int_{0}^{7} \frac{\sqrt[3]{x}+\sqrt[3]{7-x}}{\sqrt[3]{x}+\sqrt[3]{7-x}} d x \\ &2 I=\int_{0}^{7} 1 . d x \end{aligned}

\begin{aligned} \\ &2 I=(x)_{0}^{7} \\ &2 I=7 \\ &I=\frac{7}{2} \end{aligned}

Posted by

infoexpert23

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question