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Explain solution RD Sharma class 12 Chapter 19 Definite Integrals Exercise Revision Exercise question 69

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Answer: 12

Hint: To solve the given statement we have to integrate them individually

Given:  \int_{0}^{3}\left(x^{2}+1\right) d x


\begin{aligned} &=\int_{0}^{3} x^{2} d x+\int_{0}^{3} 1 d x \\ &=\left[\frac{x^{3}}{3}\right]_{0}^{3}+[x]_{0}^{3} \\ &=\left[\frac{27}{3}-\frac{0}{3}\right]+[3-0] \\ &=9+3 \\ &=12 \end{aligned}      


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