Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 chapter 19 Definite Integrals exercise Fill in the blanks question 9 maths textbook solution

Please solve RD Sharma class 12 chapter 19 Definite Integrals exercise Fill in the blanks question 9 maths textbook solution

Answers (1)

best_answer

Answer: It depends only on d.

Hint: Use \int x^{n} d x

Given: \int_{-2}^{2}\left(a x^{5}+b x^{3}+c x+d\right) d x

Solution:  

\mathrm{I}=\int_{-2}^{2}\left(a x^{5}+b x^{3}+c x+d\right) d x

    =\left[\frac{a x^{6}}{6}+\frac{b x^{4}}{4}+\frac{c x^{2}}{2}+d x\right]_{-2}^{2}

    =\left[\frac{a(2)^{6}}{6}+\frac{b(2)^{4}}{4}+\frac{c(2)^{2}}{2}+d(2)\right]-\left[\frac{a(-2)^{6}}{6}+\frac{b(-2)^{4}}{4}+\frac{c(-2)^{2}}{2}+d(-2)\right]

    \begin{aligned} &=\frac{a(2)^{6}}{6}+\frac{b(2)^{4}}{4}+\frac{c(2)^{2}}{2}+2 d-\frac{a(2)^{6}}{6}-\frac{b(2)^{4}}{4}-\frac{c(2)^{2}}{2}+2 d \\\\ &=4 \mathrm{~d} \end{aligned}

Thus, it depends only on d.

 

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10, 12 compartment 2024 exams today for 2.5 lakh students; exam timings, guidelines
anam-khan

CBSE compartment admit card 2024 out at cbse.gov.in; exams from July 15
anam-khan

Reports saying CBSE cannot conduct board exams twice a year currently ‘totally incorrect’; board denies claims

Latest Question