Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution for RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.4 (b) Question 3 maths textbook solution.

Explain solution for  RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.4 (b) Question 3 maths textbook solution.

Answers (1)

Answer : \frac{\pi}{4}

Hints:- You must know the integration rules of trigonometric functions and its limits

Given : \int_{0}^{\pi / 2} \frac{\sqrt{\cot x}}{\sqrt{\cot x}+\sqrt{\tan x}} d x

Solution : I=\int_{0}^{\pi / 2} \frac{\sqrt{\cot x}}{\sqrt{\cot x}+\sqrt{\tan x}} d x                                     .....(1)

               I=\int \frac{\sqrt{\tan x}}{\sqrt{\tan x}+\sqrt{\cot x}}                                                 .....(2)

Adding (1) and (2)

              \begin{aligned} &2 I=\int_{0}^{\pi / 2} \frac{\sqrt{\tan x}+\sqrt{\cot x}}{\sqrt{\tan x}+\sqrt{\cot x}} d x \\ &2 I=\int_{0}^{\pi / 2} 1 \cdot d x \\ &2 I=[x]_{0}^{\pi / 2} \end{aligned}

             \begin{aligned} &I=\frac{1}{2} \times \frac{\pi}{2} \\ &=\frac{\pi}{4} \end{aligned}       

Posted by

infoexpert23

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question