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  • Explain solution RD Sharma class 12 Chapter 19 Definite Integrals Exercise Revision Exercise question 36

Explain solution RD Sharma class 12 Chapter 19 Definite Integrals Exercise Revision Exercise question 36

Answers (1)

Answer:  0

Hint: To solve the equation, the value of negative is always zero

Given:  \int_{-a}^{a} \frac{x e^{x^{2}}}{1+x^{2}} d x

Solution:

\begin{aligned} &\int_{-a}^{a} f(x) d x=\int_{-a}^{a} f(a-a-x) d x \\ & \end{aligned}

=\int_{-a}^{a} f(-x) d x

\begin{aligned} &=-\int_{-a}^{a} f(x) d x \\ & \end{aligned}

I=\int_{-a}^{a} \frac{(-x) e^{x^{2}}}{1+x^{2}} d x \\

2 I=0 \\

I=0

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