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Please solve RD Sharma class 12 chapter Determinants exercise 5.1 question 11 maths textbook solution

Answers (1)

Answer:

x=2

Hint:

Take determinant of matrix on both side and equate it.

Given:

\left|\begin{array}{lll} x^{2} & x & 1 \\ 0 & 2 & 1 \\ 3 & 1 & 4 \end{array}\right|=28

Solution:

\begin{aligned} &x^{2}(8-1)-x(0-3)+1(0-6)=28\\ &8 x^{2}-x^{2}+3 x-6=28\\ &7 x^{2}+3 x-34=0\\ &(7 x+17)(x-2)=0\\ &(\mathrm{x}=2) \text { or }\left(\mathrm{x}=\frac{-17}{7}\right)\\ &\mathrm{x}=\frac{-17}{7} \text { is not integer. So, } \mathrm{x}=2 \end{aligned}

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Gurleen Kaur

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