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  • explain solution RD Sharma class 12 chapter 5 Determinants exercise Fill in the blanks question 20 maths

explain solution RD Sharma class 12 chapter 5 Determinants exercise Fill in the blanks question 20 maths

Answers (1)

Answer: -64

Hint: Here, we use basic concept of determinant

            |K A B|=K^{n}|A||B|

Given:  n = 3

            \left | A \right |=-2

            \left | B \right |=4

Solution: A and B are 3\times 3 order of matrix

            So, n = 3

            Here, \left | 2AB \right |\; \; \; \; \; \; \; So,K=2

So, now

            |K A B|=K^{n}|A||B|

            |2 A B|=2^{3} \times-2 \times 4 \; \; \; \; \; \; \; \; \; \quad[n=3,|A|=-2,|B|=4]

            \begin{aligned} &|2 A B|=8 \times-2 \times 4 \\ &|2 A B|=8 \times-8 \\ &|2 A B|=-64 \end{aligned}

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