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Name: Explain solution RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 8 maths
Uploaded: Fri, 2021-08-20 16:46
Description: Explain solution RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 8 maths

#CBSE 12 Class
#R.D. Sharma
#Definite Integrals
#Maths
#School
#RD Sharma Vol. 2 Class 12

#1.3
#10.1
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#19.1
#19.2
#19.3
#19.4 (a)
#19.4 (b)
#19.5
#Revision Exercise (RE)

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Explain solution RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 8 maths

Answers (1)

Answer: $\frac{\pi }{4}$

Hint: You must know the integration rules of trigonometric function with its limits

Given: $\int_{0}^{1} \frac{1}{x^{2}+1} d x$

Solution: $\int_{0}^{1} \frac{1}{x^{2}+1} d x$

$\begin{aligned} &=\left[\tan ^{-1} 1-\tan ^{-1} 0\right] \\\\ &=\frac{\pi}{4}-0 \\\\ &=\frac{\pi}{4} \end{aligned}$

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Explain solution RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 8 maths

Answers (1)

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