Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.3 Question 1 Subquestion (iv) Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 19 Definite Integrals Exercise 19.3 Question 1 Subquestion (iv) Maths Textbook Solution.

Answers (1)

Answer:  1

Hint: Break the range of integration  \left\{\begin{array}{c} -1<x<0 \\ 0<x<2 \end{array}\right\}

Given:   \int_{-1}^{2} \frac{|x|}{x}

Solution:

                \begin{aligned} &|x|=\left\{\begin{array}{l} -x, \text { if }-1 \leq x \leq 0 \\ x, \text { if } 0 \leq x \leq 2 \end{array}\right\} \\ \end{aligned}

                \frac{|x|}{x}=\left\{\begin{array}{l} -1,-1<x<0 \\ 1,0<x<2 \end{array}\right\} \\

                I=\int_{-1}^{0}(-1) d x+\int_{0}^{2}(1) d x

 

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question