Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 13 maths textbook solution

Please solve RD Sharma class 12 chapter 19 Definite Integrals exercise Very short answer type question 13 maths textbook solution

Answers (1)

Answer: \sqrt{2}

Hint: You must know the integration rules of trigonometric function with its limits


Given: \int_{0}^{\frac{\pi}{2}} \sqrt{1-\cos 2 x} \; d x

Solution:  \int_{0}^{\frac{\pi}{2}} \sqrt{1-\cos 2 x} \; d x

\begin{aligned} &=\int_{0}^{\frac{\pi}{2}} \sqrt{2 \sin ^{2} x} \; d x \\\\ &=\int_{0}^{\frac{\pi}{2}} \sqrt{2} \sin x\; d x \end{aligned}

\begin{aligned} &=\sqrt{2}[-\cos x]_{0}^{\frac{\pi}{2}} \\\\ &=\sqrt{2}\left[-\cos \frac{\pi}{2}+\cos 0\right] \\\\ &=\sqrt{2} \end{aligned}

 

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam Dates 2027 LIVE: Class 10th, 12th time table soon; timings, guidelines for students
anam-khan

CBSE invites LOC submission for Class 12 re-exams 2026 in West Asian countries
anam-khan

CBSE Datesheet 2027 LIVE: Class 10, 12 board exam timetable soon; sample question papers, marking scheme

Latest Question