Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 Chapter Definite integrals exercise 19.2 question 36 maths textbook solution.

Please solve RD Sharma class 12 Chapter Definite integrals exercise 19.2 question 36 maths textbook solution.

Answers (1)

Answer: \pi -2

Hint: use indefinite integral formula and the limits to solve this integral.

Given: \int_{0}^{\frac{\pi}{2}}x^2\sin x dx

Solution: \int_{0}^{\frac{\pi}{2}}x^2\sin x dx

Applying integration by parts method, then,

\begin{aligned} &=\int_{0}^{\frac{\pi}{2}} x^{2} \sin x \mathrm{~d} x=\left[x^{2} \int \sin x \mathrm{~d} x\right]_{0}^{\frac{\pi}{2}}-\int_{0}^{\frac{\pi}{2}}\left\{\frac{d\left(x^{2}\right)}{d x} \int \sin x d x\right\} d x \\ &=\left[x^{2}(-\cos x)\right]_{0}^{\frac{\pi}{2}}-\int_{0}^{\frac{\pi}{2}} 2 x(-\cos x) d x \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \quad\left(\frac{d\left(x^{n}\right)}{d x}=n x^{n-1}, \int \sin a x d x=\frac{-\cos a x}{a}\right) \\ &=-\left[x^{2} \cos x\right]_{0}^{\frac{\pi}{2}}+2 \int_{0}^{\frac{\pi}{2}} x \cos x d x \end{aligned}

On applying integration by parts method
\begin{aligned} &=-\left[\left(\frac{\pi}{2}\right)^{2} \cos \frac{\pi}{2}-0^{2} \cos 0\right]+2\left[\left\{x \int \cos x d x\right\}_{0}^{\frac{\pi}{2}}-\int_{0}^{\frac{\pi}{2}}\left\{\frac{d(x)}{d x} \int \cos x d x\right\} d x\right] \\ &=-\frac{\pi^{2}}{4} \cdot 0-0+2\left\{[x \sin x]_{0}^{\frac{\pi}{2}}-\int_{0}^{\frac{\pi}{2}} 1 \cdot \sin x d x\right\} \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \quad\left[\begin{array}{l} \because \frac{d}{d x}\left(x^{n}\right)=n x^{n-1} \\ \int \cos x d x=\sin x \end{array}\right] \\ &=2\left[\frac{\pi}{2} \cdot \sin \frac{\pi}{2}-0 \cdot \sin 0\right]-2[-\cos x]_{0}^{\frac{\pi}{2}} \\ &=\pi .1+2\left[\cos \frac{\pi}{2}-\cos 0\right]=\pi+2[0-1] \\ &=\pi-2 \end{aligned} \quad\left[\begin{array}{c} \cos \frac{\pi}{2}=0 \\ \left.\sin \frac{\pi}{2}=1\right] \\ \end{array}\right.


 

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 result verification 2024 application out at cbse.gov.in; last date, fees
anam-khan

CBSE results 2024 later for 102 students over fake certificates; board issues show cause notice
anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know

Latest Question