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  • Provide solution for RD Sharma maths class 12 chapter 19 Definite Integrals exercise Very short answer type question 43

Provide solution for RD Sharma maths class 12 chapter 19 Definite Integrals exercise Very short answer type question 43

Answers (1)

best_answer

Answer: 0

Hint: you must know the rule of integration

Given: \int_{1}^{2} \log _{e}[x] d x

Solution:  \int_{1}^{2} \log _{e}[x] d x

Using rule of greatest integer

\begin{aligned} & \int_{0}^{1} 0 d x+\int_{1}^{2} 1 d x+\int_{2}^{3} 2 d x \\\\ I=& \int_{1}^{2} \log [x] d x=\int_{0}^{1} \log (0) d x+\int_{1}^{2} \log 1 d x \\\\ =& 0 \end{aligned}

 

 

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