Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 18 Subquestion (ii) Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 18 Subquestion (ii) Maths Textbook Solution.

Answers (1)

best_answer

Answer: X = \begin{bmatrix} -2 &\frac{-10}{3} \\ \\ 12 &\frac{14}{3} \\ \\ \frac{-31}{3} & \frac{-7}{3} \end{bmatrix}

Hint: Take the variable 3X into RHS and 5B into LHS. Then, solve.

Given:A =\begin{bmatrix} 8 & 0\\ 4&-2 \\ 3&6 \end{bmatrix} , B =\begin{bmatrix} 2 &-2 \\ 4& 2\\ -5& 1 \end{bmatrix} , 2A + 3X = 5B

Here, we have to compute X.

Solution:

2A + 3X = 5B

2\begin{bmatrix} 8 & 0\\ 4& -2\\ 3&6 \end{bmatrix} + 3X = 5\begin{bmatrix} 2&-2 \\ 4 &2 \\ -5 &1 \end{bmatrix}

\begin{bmatrix} 16 & 0\\ 8& -4\\ 6&12 \end{bmatrix} + 3X = \begin{bmatrix} 10&-10 \\ 20 &10 \\ -25 &5 \end{bmatrix}

3X = \begin{bmatrix} 10&-10 \\ 20 &10 \\ -25 &5 \end{bmatrix}-\begin{bmatrix} 16 & 0\\ 8& -4\\ 6&12 \end{bmatrix}

3X = \begin{bmatrix} -6 &-10 \\ 12 &14 \\ -31 &-7 \end{bmatrix}

X = \frac{1}{3}\begin{bmatrix} -6 &-10 \\ 12 &14 \\ -31 &-7 \end{bmatrix}

X = \begin{bmatrix} -2 &\frac{-10}{3} \\ \\ 12 &\frac{14}{3} \\ \\ \frac{-31}{3} & \frac{-7}{3} \end{bmatrix}

 

 

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Don't stress about syllabus volume, prioritise, revise: Toppers share exam tips during PPC 2025
anam-khan

Feedback on CBSE question papers 2025 'vague, unclear'; board has 3 requests for schools
anam-khan

CBSE exam paper leak rumours ‘baseless’, board to take legal action after a video goes viral

Latest Question