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Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 16 Maths Textbook Solution.

Answers (1)

Answer:x = 2, y = -8
Hint: Add LHS part and then equate with RHS part.

Given: 2\begin{bmatrix} 3 & 4\\ 5 & x \end{bmatrix} + \begin{bmatrix} 1 &y \\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 7 &0 \\ 10& 5 \end{bmatrix}
Here, we have to compute x and y.
Solution:

2\begin{bmatrix} 3 & 4\\ 5 & x \end{bmatrix} + \begin{bmatrix} 1 &y \\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 7 &0 \\ 10& 5 \end{bmatrix}

\begin{bmatrix} 6 & 8\\ 10 &2 x \end{bmatrix} + \begin{bmatrix} 1 &y \\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 7 &0 \\ 10& 5 \end{bmatrix}

\begin{bmatrix} 6+1 & 8+y\\ 10+0 &2 x+1 \end{bmatrix} = \begin{bmatrix} 7 &0 \\ 10& 5 \end{bmatrix}

\begin{bmatrix} 7 & 8+y\\ 10 &2 x+1 \end{bmatrix} = \begin{bmatrix} 7 &0 \\ 10& 5 \end{bmatrix}
Equating this, we get:
8+y = 0   
\Rightarrow y= -8
Also,
2x +1 = 5
2x = 4
\Rightarrow x =2

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infoexpert27

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