Get Answers to all your Questions

header-bg qa

Please Solve RD Sharma Class 12 Chapter Algebra of Matrices Exercise 4.2 Question 15 Subquestion (ii) Maths Textbook Solution.

Answers (1)

Answer:  x = 1, y = 3\: and\: z = 10

Hint: Solve LHS and then equate with RHS.

Given:    \begin{bmatrix} x & y+z & z-3 \end{bmatrix}+\begin{bmatrix} y & 4 & 5 \end{bmatrix}= \begin{bmatrix} 4 & 9 & 12 \end{bmatrix}

Here, we have to compute x , y and z.

Solution:

\begin{bmatrix} x & y+2 & z-3 \end{bmatrix}+\begin{bmatrix} y & 4 & 5 \end{bmatrix}= \begin{bmatrix} 4 & 9 & 12 \end{bmatrix}

\begin{bmatrix} x+y & y+2+4 & z-3+5 \end{bmatrix}= \begin{bmatrix} 4 & 9 & 12 \end{bmatrix}

Equating this, we get:

x+y = 4                                                                                       …(1)

Also,

y + 6 = 9
\Rightarrow y = 3                                                                                                 
z + 2 = 12
\Rightarrow z = 10

Applying the value of ‘y’ in equation (1), we get:

x + 3 = 4
x = 1

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads